1 · Procedure
Place four small ohmic contacts on the perimeter of a thin, simply-connected sample. Number them 1, 2, 3, 4 in order. Make two resistance measurements:
- RA = V43 / I12 — current through 1→2, voltage between 4 and 3.
- RB = V14 / I23 — current through 2→3, voltage between 1 and 4.
The sheet resistance Rs satisfies van der Pauw’s relation:
There is no closed-form inverse, so we solve numerically. Once Rs is known, the resistivity for a film of thickness t is simply ρ = Rs · t.
2 · The symmetric limit
When RA = RB ≡ R, the equation collapses to 2 exp(−π R / Rs) = 1, so:
This is the famous Van der Pauw constant π/ln 2 ≈ 4.5324. It is the only case with a closed-form solution.
3 · Numerical method
Let z = 1/Rs. Starting from the symmetric guess z₀ = 2 ln 2 / (π (RA + RB)), we iterate:
This is a damped Newton step with very fast quadratic convergence — typically ten to fifteen iterations suffice for double-precision residuals.